Well, my strategie is that I by now know certain numbers I can make easily with 1 or 2 4's, that I can use (like I dont see a 4! as 4! but as 24, I see a 4!/.4 as 60, I see a 4^4 as 256 etc.) So for me it is not really how do I make a number with 4 4's, but how do I make a number by adding and subtraction using a combination of 2's, 4's, 8's, 16's, 24's, 60's, 12's, 44's etc. If I cant figure out a way like that, I start to look at ways to make the number by multiplying or dividing a cobination of those listed numbers, if I cant find a way then by using more difficult features like ! or powers, roots, ↑↑, logaritms (although those are forbidden sadly). Luckily it hasnt been that hard yet though so I could mostly do it with the substraction and addition method still . As for 76: 4!/.4 + 4*4 EDIT: Also, looking at the previous couple of answers can be helpful too, since the next number usually isnt that different. For example: for 63 you could do something like (4^4-4)/4. If you then get 65, it is an easy change of a - to a +: (4^4+4)/4.
even though I don't really understand it, (if it goes by the defenition of what Tom said, your answer should be nagative, right? ) I think it'll be fine, as long as it doesn't end up in every next one being really easy (like with the logs, You can make it such that the next one is just adding another square root: that's no fun, so I excluded it ) 80 = 4* (4P4-4)
I don't think it would be negative... Gamma ( sqrt (4)) is the same as gamma (2), which is 1!, obviously creating 1. So the whole thing is (4-1)^4-sqrt(4), going to 81-2, equalling 79 (unless I'm just being stupid somewhere... EDIT: (4! / .4) + 4! – sqrt (4) = 82
oops, I read 4- (gamma (sqrt (4))^4 instead of (4- gamma (sqrt (4))^4... suttle diferences... (It's late for me: I amn't going to post another one now)
83 = (4!-sqrt(4))*4-4!!!! 4!!!! is an easier way to get 1 than the gamma way, lol. Also, don't forget about inverse gamma
Y’all are making this too hard for my brain to handle… 84 = 44*sqrt(4)-4 EDIT: are we allowed to use 44?
As long as you count it as two, it should be fine This one is a bit sketchy, though. 44*√4 - 4 + e^(lim(4/x), x -> ∞) [EDIT] Oh wait, that's 5. Carry on.
I feel like limits are cheating, even though I would love to do an EMC calc lesson and then all use them Otherwise you can do any number with just a simple lim(x->4/4)(x+x+x+x...x)
