There is no way to solve a variable equation if we are unaware of the desired result from the equation. I presume you mean solve for x? 341x5 Edit: obviously x could be anything though as the equation is a bit loaded
I guess he justs wants us to give the total. It is 0 for any x. 341 * 5 = 1705 Determine the second order partial derivatives of f(x,y) = x³+x²y³ - 2y²
There is a *0 so the answer is 0, no matter what x is. And to answer yours, = 1705 Now for my equation: sum [(4/5)^n], n=0 to infinity Edit: Is this right? f(2,0)(x,y) = 6x + 2y^3 That's only the second order for both x's, so I'm probably missing something.
It is not infinity, try again 2x + 4 My problem still stands to be solved: sum [(4/5)^n], n=0 to infinity
Simple is a relative term The numbers being added together get smaller and smaller as you go along, so the total sum approaches a single particular number. for a way to solve it Google "geometric series" and it should give you the equation for it.
But... there is no equation so 6 I guess, What is the square root of 666? Yea I kept it very simple as I want to abide to the op