Problem 3: Put 3 boxes on each side of the scale. If one weighs more, remove the other two sets of three boxes. If they weigh the same, remove the two sets that were weighed. Put 1 of the remaining 3 boxes on each side of the scale. Repeat steps above. The only remaining box contains the paper. IGN: Defne_b_ded
Also, can we suggest problems for following challenges? A suggestion would of course exclude us from winning, and be based on the trust that I wouldn't simply tell my friends the answer. Though, if you ask my friends, I would have much more fun making them try to guess it than cheating the system.
Problem #3: There are 9 cushioned boxes that looks and weighs exactly the same. Jack puts one slip of paper in one of the boxes, then mixes the boxes up again. Using only a scale with no weighs or anything else, how can you find the box with the slip of paper in it while using the scale the least amount of times? Problem#: 3 Answer: Explanation make towers of 3 the boxes and measure the one that weight the most passes to the second test ill measure 2 of the boxes is one is heavier than the other, then is that one, if both measure the same the on with the slip will be the one i didn't measure In other words(although is number, lel!):5 IGN: you can just look that(<---)way but if you cant for some reason, it is tuqueque