[Legal counting forum game] Counting with four fours

Discussion in 'Forum Games' started by Egeau, Jan 11, 2018.

  1. 14 = 4! / (Squareroot: 4) + 4 / (Squareroot: 4)
  2. Finally one I can figure out. :p
    15 = -4/4 + 4(4)
    Or, written in a more reasonable manner... 15 = 4 * 4 - 4 / 4
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  3. Yay. I'll try to be creative. It's harder than I expected though. Here is 16.

  4. lim (x^√x)+(x/x)+(4*(4-4)), x->4

    Hey, it only uses the number 4 4 times ¯\_(ツ)_/¯
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  5. 18 = (4!+4!+4!)/4
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  6. 19 = 4! - 4 - (4/4)
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  7. 20 = 4*4 + √(4*4)
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  8. 21:

    ( 4^(ln(e^(ln(e)))) * sqrt(4) + (ln(4)/elog(4))) + ( 4!/sqrt(4) - (sqrt(4)log(4)) )

    I know I used log, but ln is a log too and I didnt use it in any way like you have shown in the OP (also you could do it way more easier with (4 + 4 + (whatever number you want to get in 4's) )/4 so yeah..."

    Also sqrt actually could be considered having a 2 with it... or you would have to write it as (4+4)√((whatever you want in your sqrt)^4)

    Also I wonder if anyone is even going to attempt verifying these answers :p
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  9. 22
    4+4+4+4+4+(4/4)+(4/4)
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  10. Rule: "...only using four fours..."

    So I think we're still looking for 21?

    I'm checking them quietly. Because if I think an answer is wrong, it's probably my own mistake.
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  11. Whoops! My bad :3. For some reason I completely skipped the part where it said four :p.

    Let me redo this then :3, since my first version was only with alot of nonsense thrown in between to make it look more complicated :rolleyes:.

    4 * (4 + ln(e)) + 4/4
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  12. I'm just going to be anooying here :p

    Isn't e also a number...
    I said e^x is legal as that is a function of sorts (you use it everywhere) but e or e^1 is a number, no doubt about it :p
  13. You have the right to :p.

    But for example, if I would change the ln(e) to ln(e^x)/x would that be allowed then? since I dont really change anything but I do use the ^x now...

    EDIT: I realize that it would be the same as dividing x by x to get 1, which kinda doesnt make this the best thing to use here because then you could just x/x + x/x + x/x... etc but maybe it is allowed?
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  14. Well, I ment e^x as in e^4 or e^4*4 I personally wouldn't know how to use it, but e^x is a function of sorts with x being just any odd thing you'd like to ad. not keeping the x... that is kind of silly...
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  15. This is getting more interesting with rule discussion and such. :p
    I suspected some of the issues haastregt is suggesting, when I first read the rules... but I thought I'd keep quiet about them, as I'm not too good at maths at the moment. :p
  16. Let's get this back on track. 4!-4+(4/4)
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  17. 22 = 4!-(4+4)/4
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  18. 23 ~= 4^(e-.44) -.4 :p
  19. Nice. This should be a nice addition. 44 / sqrt(sqrt(4*4)).
    In the above counting I used concatenation meaning 4 || 4 = 44.

    I thought what could be the biggest number you can make with only four 4's. First let's try an obvious example, something like 4^4^4^4 = 256^256 ~ 3.4 * 10^38. Yes, very big. With the silly exception using the exponential function gives e^(4^4^4^4) which is much bigger but is a very silly answer if you ask me... :p
    Thus, using concatenation we could try 4^444 = 2.1 * 10^267. MUCH bigger! Maybe 44^44 is an option?
    44^44 = 2.1 * 10^72. Not that large, huh. It's only the amount of atoms on earth, times one BILLION.

    So the biggest number I found was 4^444 :D Will update later.

    And here is 24, as writing this post took so long: 24 = 4 * 4 + 4 + 4
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  20. im pretty sure theres some integral like
    fnInt(-44,44)X^Xdx or something that's bigger. the rules arent exactly clear on using X or not, but if it is then its big.
    Also if you count the use of e, then it can be infinitely big, e^e^e^e^e^e^e^4444 :p
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